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online tutor Michigan Technological University Geometry Algebra Physics Pre-Calculus Pre-Algebra tutoring
26 0

Jake K.

Michigan Technological University, Class of 2015

Major: Mechanical Engineering

See all Jake's info

Teaching Experience

I have been tutoring in Mathematics for over 4 years. I address any topics not fully understoond and illustrate the correct way to approach them. In High School I was a volunteer student mentor for those struggling in Mathematics and Physics. In College I have filled a similar role working with those whose needs were not sufficiently answered by the teachers and TA's. I am most often asked questions in Statics, Dynamics and Thermodynamics, but do also deal with those in the Calculus sequence including Differential Equations and Linear Algebra. I enjoy teaching others and helping them achieve their educational goals. I also believe students benefit from seeing a subject from a different perspective. The "ah-ha" moment is always one of the best to witness.

Extracurricular Interests

I was born and raised in Traverse City, Michigan. I have since moved to Houghton, Michigan to attend college at Michigan Technological University. Outside of my direct schooling, I spend a decent portion of my time with SAE Baja and I will soon join the Aerospace Enterprise Team. These teams have been a magnificent opportunity to apply what I have learned and help strengthen the principles I've learned in school. With my free time I often spend time on the internet learning about US History, Political Theory, Quantum Mechanics, General Physics, Economics and Astronomy. This is often supplemented by Khan Academy and Youtube channels such as MinutePhysics, Veritasium, Numberphile, and NottinghamScience. Past that I also enjoy spending my time playing my drumset, swimming, and skiing.

Top Subjects

Mechanical Engineering

I have been interested and involved in Mechanical Engineering since Middle School. In High School I was a part of the Robotics Team, and chose to do an honors contract for Physics, which meant building projects throughout the semester (trebuchets, propulsion system for a foam car, catapult, maglev vehicle). In College I joined the SAE Baja and competed in 5 events. By the end of my Sophomore term I was the Lead Pit Captain and was often consulted for mathematical, computational assistance. In College I also joined the Honors program. For Honors Physics I built a floating arm trebuchet and had to design and run several experiments using it. This semester (Spring 2014) I am joining the Aerospace Enterprise at MTU and will be a member of the Structural Systems branch. I have always been at the top of my class, and my Mechanical Engineering classes are no exception.

Physics

As explained above, I have been very involved in with Physics and helping others understand it. I have found that using examples gained from my real world experience and projects help the student to visualize the abstract concepts taught in lecture.

Mechanical Engineering "On top of being easy to communicate with, he took his time to make sure I understood every step he took along the problem. And in addition to offering his own advice and strategies he personally preferred to solve the problem, he also did well in learning the particular method my professor normally uses to solving the problems in class. Will not offer advice in scenarios he is unsure of or at least cautions that he is not confident in those specific scenarios."
Physics This is a review for a written lesson.
Basic Physics This is a review for a written lesson.
Basic Physics This is a review for a written lesson.
Basic Physics This is a review for a written lesson.
Basic Physics This is a review for a written lesson.
Physics This is a review for a written lesson.
Physics This is a review for a written lesson.
Physics This is a review for a written lesson.
Physics This is a review for a written lesson.
1-10 of 26 Reviews

Subject: Basic Physics

Someone asked:

I decided to drop my class because I didn't get in to my doctorate program. One of my transcripts didn't make it by the deadline and now I can't reapply for another year! Not sure if I want to go through all of it again next year, so I am dropping for now. Thanks for all your help. Instaedu already charged me for this week, so I wanted you to have it. Thanks again.

Jake responded:

Dang. I'm really sorry to hear that. Seriously. I have a lot of friends in that same boat, and I've seen how infuriating the entire process can be. Thanks for having me as your tutor, and I'm happy I could help when I could. I wish you the best of luck in the future Ali.

Subject: Basic Physics

Someone asked:

Here are the answers to those mutual inductance questions...

27. Mean Radius = l = 10cm = 0.1m
Cross Sectional Area = A = 4cm^2 = 4*10^-4 m^2
Number of turns in the inner solenoid = N1 = 100
Number of turns in the outer solenoid = N2 = 500
mu = constant = 4*pi*10^-7 H/m
Therefore,
Mutual Inductance = M = mu*N1*N2*A*l = 4*pi*(10^-7)*100*500*(4*10^-4)*0.1
M = 2.5*10^-6

29. a) di/dt = Rate of current = 0.242A/s
Induced emf = V = 1.65mV = 1.65*10^-3 V
Now,
Induced emf = (Mutual Inductance)*(Rate of Current)
V = M*(di/dt)
1.65*10^-3 = M*0.242
Therefore,
M = Mutual Inductance = 6.818*10^-3

b) Number of Turns = N = 25
Current = i = 1.2A
Flux = N*i = 25*1.2
Therefore,
Flux = 30

c) di/dt = 0.360 A/s
Mutual Inductance = M = 6.818*10^-3 (Calculated in part (a))
Now,
Induced emf = M*di/dt = (6.818*10^-3)*0.36
Hence,
Induced emf = 2.45*10^-3 V = 2.45 mV

32. a) H = 4.5*10^-3
Number of coils = N = 125
Current = i = 11.5 A
Assumption : (Outer Radius/Inner Radius) = 2
mu = constant = 4*pi*10^-7
Magnetic Flux Through Each Loop = [(mu*N*i*H)/(2*pi)]*ln(Outer Radius/Inner Radius)
i.e. Magnetic Flux Through Each Loop = [((4*pi*10^-7)*125*11.5*4.5*10^-3)/(2*pi)]*ln(2)
Therefore,
Magnetic Flux Through Each Loop = 8.96*10^-7 T

33. Rate of current = di/dt = 0.0640 A/s
Self-Induced emf = 0.016 V
Inductance of the Inductor = L
Now,
Self-Induced emf = (Inductance of the Inductor)*(Rate of current)
i.e. 0.016 = L*0.064
Therefore,
L = Inductance of the Inductor = 0.25

Jake responded:


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Subject: Basic Physics

Someone asked:

To submit answers for Sunday

Jake responded:

Hey Ali.

Sorry this took me so long to get to you. This week has been absolutely crazy for me. It was exam week and this week I have a lot of projects due. So again, sorry about the time it has taken to get this to you.

If you are willing to send me the solutions they offer you, that would be awesome. I always want to make sure I know as much about the subjects I am tutoring as possible.

And no, I don't think you owe me any extra time for the ones I tried to do. You have been very generous and it was my fault for not reading it over prior anyways.

I can do the extra problem if you like, but I probably won't be able to do it until around 10:00pm EST due to team meetings and project work. If you would still like me to do it however, I can. Just let me know.

  • Ali-Instaedu.pdf This attachment has been locked.

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Subject: Basic Physics

Someone asked:

Here is the pic for # 9 and 14, and adding time

Jake responded:

Sounds good.

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Subject: Basic Physics

Someone asked:

It wouldn't take all three images at one time and I am adding time. This is for #2

Jake responded:

Thats kind of weird, but the same thing happens when I try to upload more than 1 pdf.

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Subject: Physics

Someone asked:

Here are this weeks questions. I don't need them until Sunday, but just sumbit something by Friday before we lose the time for this week. It says it refreshes at 1:59 am on March 1. But then you can submit the rest by Sunday evening. And Spring Break starts the 7th, so you have a free week coming to you, and I will just give the time to you.

2. The magnetic field B in a certain region is 0.128 T, and its direction is that of the +z axis in Figure21.47 (below). a) What is the magnetic flux across the surface abcd in the figure? b) What is the magnetic flux across the surface befc? c) What is the magnetic flux across aefd? d) What is the net flux through all five surfaces that enclose the shaded volume?

6. In a physics laboratory experiment, a coil with 200 turns enclosing an area of 12 cm^2 is rotated from a position where its plane is perpendicular to the earth's magnetic field to one where its plane is parallel to the field. The rotation takes 0.040 s. The earth's magnetic field at the location of the laboratory is 6.0 x 10^-5 T. a) What is the total magnetic flux through the coil before it is rotated? After it is rotated? b) What is the average emf induced in the coil?

9. A 30 cm x 60 cm rectangular circuit containing a 15 ohm resistor is perpendicular to a uniform magnetic field that starts out at 2.65 T and steadily decreases at 0.25 T/s. See figure 21.48 below. While this field is changing what does the ammeter read?

14. Using Lenz's law, determine the direction of the current in resistor ab of figure 21.52 when a) switch S is opended after having been closed for several minutes; b)coil B is brought closer to coil Awith the switch closed c)the resistance of R is decreased whiel the switch remains closed.

22. When a thin 12.0 cm iron rod moves with a constanct velocity of 4.50 m/s perpendicular to the rod in the direction shown in Figure 21.59, the induced emf across its ends is measured to be 0.450 V. a) What is the magnitude of the magnetic field? b) Which point is at a higher potential, a or b? c)If the bar is rotated clockwise by 90 degrees in the plane of the paper, but keeps the same velocity, what is the potential difference induced across its ends?

27. A toroidal solenoid has a mean radius of 10.0 cm and a cross-sectional area of 4.00 cm^2and is wound uniformly with 100 turns. A second could with 500 turns is wound uniformly on top of the first. What is the mutual inductance of these coils?

29. Two coils are wound around the same cylindrical form. When the current in the first coil is decreasing at a rate of 0.242 A/s. the induced emf in the second coil has magnitude 1.65 mV. a) What is the mutual inductance of the pair of coils? b) If the second coil has 25 turns, what is the average magnetic flux through each turn when the current in the first coil equals 1.20 A? c) If the current in the second coil increases at a rate of 0.360 A/s, what is the magnitude of the induced emf in the first coil?

32. A 4.5 mH toroidal inductor has 125 identical equally spaced coils. a) if it carries an 11.5 A current, how much magnetic flux passes through each of its coils? b) If the potential diffence across it's ends is 1.16 V, at what reate is the current in it changing?

33. At the instant when the current in an inductor is increasing at a rate of 0.0640 A/s, the magnitude of the self-induced emf is 0.0160 V. What is the unductance of the inductor?

39. You plan to take your hair blower to Europe, where the electrical outlets put out 240V instead of 120V seen in the US. The blower puts out 1600 W at 120 V. a) What could you do to operate your blower via the 240V line in Europe? c) What resistance will your blower appear to have when operated at 240V?

Jake responded:

I should have these finished by tonight. I should be able to get them to you by tomorrow evening.

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Subject: Physics

Someone asked:

Not sure what else I could have done to prepare for the test. I did fine on the problems...it was the multiple choice that got me. I missed 10 and they were 2 points a piece. Personally I think the teacher is just too smart and can't simplify it for our level. But now I know what to expect on the tests and he drops the lowest test grade, so hopefully this will be the one that is dropped. But homework, labs, and quizzes are 45% of the final grade and I am making A's on all of those, so I'll be fine. Maybe we can get him to make a study guide for the multiple choice info.

Sorry it took so long to get these to you, and of course I need them to turn in Monday, so if you can't do them all by Monday, let me know. Thanks!

1. In a 1.25 T magnetic field directed vertically upward, a particle having a charge of magnitude 8.50 muC and initually moving northward at 4.75 km/s is deflected toward the east. A) what is the sign of the charge of this particle? Make a sketch to illustrate how you found your answer. B) Find the magnetic force on the particle.

5. At a given instant, a particle with a mass of 5.00 x 10^-3 kg and a charge of 3.50 x 10^-8 C has a velocity with a magnitude of 2.00 x 10^5 m/s in the +y direction. it is moving in a uniform magnetic field that has a magnitude 0.8 T and is in the -x direction. What are a) the magnitude and direction of the magnetic force on the particle and b) it's resulting acceleration?

8. A particle with a charge of -2.50 x 10^-8 C is moving with an instantaneous velocity of magnitude 40.0 km/s in the xy plane at an angle of 50 degrees counterclockwise from the +x axis. What are the magnitude and direction of the force exerted on this particle by a magnetic field with magnitude 2.00 T in the a) -x direction, and b) +z direction?

14. An alpha particle (a He nucleus, containing two protons and two neutrons and having a mass of 6.64 x 10^-27 kg) traveling horizontally at 35.6 km/s enters a uniform, vertical, 1.10 T magnetic field. a) What is the diameter of the path followed by this alpha particle? b) What effect does the magnetic field have on the speed of the particle? c)What are the magnitude and direction of the acceleration of the alpha particle while it is in the magnetic field? d) explain why the speed of the particle does not change even though an unbalanced external force acts on it.

23. singly ionized (one electron removed) atoms are accelerated and then passed through a velocity selector consisting of perpendicular electric and magnetic fields. The electric field is 155 V/m and the magnetic field is 0.0315T. The ions next enter a uniform magnetic field of magnitude 0.0175 T tthat is oriented perpendicular to their velocity. a) How fast are the ions moving when they emerge form the velocity selector? b) If the radius of the path of the ions in the second magnetic field is 17.5 cm, what is their mass?

28. A horizontal rod 0.200 m long carries a current through a uniform horizontal magnetic field of magnitude 0.067T that points perpendicular to the rod. If the magnetic force on this rod is measured to be 0.13 N, what is the current flowing through the rod?

33. A long wire carrying 4.50 A of current makes two 90 degree bends, as shown in figure 20.64. The bent part of the wire passes through a uniform 0.240 T magnetic field directed as shown in the fugure and confined to a limited region of space. Find the magnitude and direction of the force that the magnetic field exerts on the wire.

34. The 20.0 cm by 35.0 cm rectangular circuit show in figure 20.65 is hinged along side ab. It carries a clockwise 5.00 A current and is located in a iniform 1.20 T magnetic field oriented perpendicular to two of its sides, as shown. a) make a clear diagram showing the direction of force taht the magnetic field exerts on each segment of the circuit (ab, bc, etc.) b) Of the four forces you drew in part a, decide which ones exert torque about the hinge ab. Then calculate only those forces that exert this torque. c) Use your results from part b) to calculate the torque that the magnetic field exerts on the circuit about the hinge axis ab.

49. A long, straight telephone cable contains six wires, each carrying a current of 0.300 A. The distances between the wires can be neglected. A) if the currents in all six wires are in the same direction, what is the magnitude of the magnetic field 2.50 m from the cable? b) If four of the wires carry currents in one direction and the other two carry currents in the opposite direction, what is the magnitude of the field 2.50 m from the cable?

55. (Hint: wire= 4mm separation) A 2.0 m ordinary lamp extension cord carries a 5.0 A current. Such a cord typically consists of two parallel wires carrying equal currents in opposite directions. Find the magnitude and direction (attractive or repulsive) that the two segments of this cord exert on each other. ( You will need to inspect a lamp cord at home and measure or reasonably estimate the quantities needed to do this calculation.)

73. Three long, straight electric cables, running north and south, are tightly enclosed in an insulating sheath. One of the cables carries a 23.0 A current southward; the other two carry currents 17.5 A and 11.3 A northward. Use Ampere's law to calculate the magnitude of the magnetic field at a distance of 10.0 m from the cables.

75. Platinum is a paramagnetic metal having a relative permeability of 1.00026. A) What is the magnetic permeability of platinum? B) If a thin rod of patinum is placed in an external magnetic field of 1.3500 T, with its axis parallel to that field what will be the magnetic field inside the rod?

Jake responded:

Hey so I could all of them except the very last part of the last question. I think something was either left out, or he gave an equation with very specific conditions. So that was the only one I couldn't get.

But as always, let me know if you need any clarifications.

  • InstaEdu- Ali-Mag..pdf This attachment has been locked.

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Subject: Physics

Someone asked:

I've been really busy this week and haven't had a chance to post my questions. I will first thing in the morning, but my time for this week will have run out, so I am giving it to you before it runs out. I ended up getting a 73 on my test, but on a positive note, I made the highest grade out of my group. (maybe I need a new group!) And the teacher admitted it was way too hard and too long...and he said he will make the next one easier.

Jake responded:

Ali I sincerely appreciate you giving me these hours. I'm serious. I really appreciate it.

I'm sorry the test didn't go quite as well as you would have liked. I mean those test happen though as I'm sure you know. They are just unfortunate happenings. It is refreshing to hear that you got the best out of your group though. If there is anything you think I can do better or anything else I can do to help you with test preparation, just let me know. I'm here to help and that is what I plan to do.

Thanks again Ali.

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Subject: Physics

Someone asked:

Should have new questions on Monday

Jake responded:

Sounds good to me!

Thanks again!

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Subject: Physics

Someone asked:

No more questions for this week! Had the first test yesterday...3 1/2 hours! And I wasn't even the last one to finish! But the teacher looked over my work briefly and said it looked like what he expected to see, so he thought I did fine. And he said my homework "looks beautiful!" So looks like things are moving in the right direction. I have 80 minutes left over for this week, so think of it as "paying it forward" for those times it takes longer than given. I would rather the money go to you than the company. Thanks!

Jake responded:

3.5 Hours for an exam! Talk about life draining. That's crazy; the longest one I've had to take thus far was 3 hours and I almost died during that. However, while it might have stolen apart of your soul, it is absolutely awesome to hear that you think you did well. I'm glad I can really help you grasp the concepts.

I really do appreciate the extra hours. Thanks a lot Ali and congrats.

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Subject: Physics

Someone asked:

I thought I was going to do this one on my own, but it was confusing me! See attached....

Jake responded:

SORRY ALI! I thought I submitted this one already! It must have not taken. Here you go. Sorry for the time crunch!

  • Ali-20914b.pdf This attachment has been locked.

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Subject: Physics

Someone asked:

27. When switch s is open, the voltmeter V across the battery reads 3.08 V. When the switch is closed, the voltmeter reading drops to 2.97V and the ammeter A reads 1.65 A. Find the emf, the internal resistance of the battery, and the circuit resistance R.

41. The battery for a certain cell phone is rated 3.70 V. According to the manufacturer it can produce 3.15 x 10^4 J of electrical energy, enough for 5.25 h of operation, before needing to be recharged. Find the average current that this cell phone draws when turned on.

65. A 12.4 mF capacitor is connected through a 0.895 M ohm resistor to a constant potential difference of 60.0 V. a) compute the charge on the capacitor at the following times after the connections are made: 0, 5.0 s, 10.0 s, 20.0 s, and 100.0 s. b) compute the charging currents at the same instants, c) graph the results of parts a) and b) for t between 0 and 20 s.

Jake responded:

Hey Ali,

So the quality of the copy isn't as good on these ones. The scanner I was using must have been of poorer quality than the one i normally use. I hope it is still legible and intelligible. If not, let me know.

  • Ali- 20914.pdf This attachment has been locked.

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Subject: Physics

Someone asked:

We got a 100 on the homework! YOU ROCK! Here are my questions for this week. If you don't have a chance to do them all by Friday, just give me back what you have before Friday so we use my hour this week. Last week I ended up paying the company for an hour that we didn't use, and it took an hour from this week because it wasn't returned until Saturday. I'd much rather the money go to you than the company!

1. Typical household currents are on the order of a few amperes. If a 1.50 A current flows through the leads of an electrical appliance, a) how many electrons per second pass through it b) how many coulombs pass trhough it in 5.0 min, and c) how long does it take for 7.50 C of charge to pass through?

11. An aluminum bar 3.80 m long has a rectangle cross section 1.00 cm by 5.00 cm. a) What is its resistance? b)What is the length of a copper wire 1.50 mm in diameter having the same resistance?

14. What is the resistance of a Nichrome wire at 0.0 degrees C if its resistnace is 100.00 ohms at 11.5 degrees C? The temperature coefficient of resistivity for Nichrome is 0.00040 (C)^-1.

18. The folloing measurements of current and potential difference were made on a resistor constructed of Nichrome wire, where Vab is the potential difference across the wire and I is the current through it:
I (A) 0.50 1.00 2.00 4.00
Vab(V) 1.94 3.88 7.76 15.52

a) Graph Vab as a function of I. b) Does Ohm's law apply to Nichrome? How can you tell? c) what is the resistance of the resistor in ohms?

41. The battery for a certain cell phone is rated 3.70 V. According to the manufacturer it can produce 3.15 x 10^4 J of electrical energy, enough for 5.25 h of operation, before needing to be recharged. Find the average current that this cell phone draws when turned on.

65. A 12.4 mF capacitor is connected through a 0.895 M ohm resistor to a constant potential difference of 60.0 V. a) compute the charge on the capacitor at the following times after the connections are made: 0, 5.0 s, 10.0 s, 20.0 s, and 100.0 s. b) compute the charging currents at the same instants, c) graph the results of parts a) and b) for t between 0 and 20 s.

Jake responded:

That's awesome! Really glad to help.

Okay so I probably won't have the 41 or 65 done by Friday (We have a week long carnival hosted by my school and it starts in 2 hours). So I will upload those asap.

And thank you for giving me the extra time. Much, much obliged.

  • Ali-part 1.PDF This attachment has been locked.

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Subject: Physics

Someone asked:

Not sure what happened with my last submission. I broke it up into 2 lessons and added some more time to it. I get 2 hours a week, so I already paid for it and I'd rather you get it than just pay the company. It renews every Friday, so if it is taking you longer, you just need to let me know. I don't want you to feel taken advantage of. Thanks!

11. Two large metal parallel plates carry opposite charges of equal magnitude. They are separated by 45.0 mm, and the potential difference between them is 360 V. a) What is the magnitude of the electric field (assumed to be uniform) in the region between the plates? b) What is the magnitude of the force this field exerts on a particle with charge +2.40 nC?

20. a) An electron is to be accelerated from 3.00 x 10^6m/s to 8.00x10^6 m/s. Through what potential difference must the electron pass to accomplish this? b)Through what potential difference must the electron pass if it is to be slowed from 8.00 x 10^6 m/s to a halt?

30. A +5.00 pC charge is located on a sheet of paper. a) Draw to scale the curves where the equipotential surgaces due to these charges intersect the paper. Show only the surgaces that have a potential (relative to infinity) of 1.00 V, 2.00 V, 3.00 V, 4.00 V, and 5.00 V. b) The surfaces are separated equally in potential. Are they also separated equally in distance? In words describe the shape and orientation of the surfaces you just found.

37. The plats of a parallel -plate capacitor are 2.50 mm apart, and eash has an area of 12.2 cm^2. Each plate carries a charge of magnitude 4.35 x 10^-8C. The plates are in vacuum. a) What is the capacitance? b) What is the potential difference between the plates? c) What is the magnitude of the electric field between the plates?

42. A 10.0 mF parallel-plate capacitor is connected to a 12.0V battery. After the capacitor is fully charged, the battery is disconnected without loss of any of the charge on the plates. a) A volt-meter is connected across the two plates without discharging them. What does it read? b) What would the volt meter read if i) the plate separation was doubled ii) the radius of each plate was doubled, but the separation between the plates was unchanged?

Jake responded:

Hey Ali, This problem set didn't take me too much longer than you paid me for it, so it's not a big deal. As the semester progress, that might become more important, so I'll let you know when/if that starts to happen.

I fixed #59 and uploaded it with this set. Let me know if there is anything you can read or still do not understand.

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Subject: Physics

Someone asked:

59. a) How much charge does a battery have to suply to a 5.0mF capacitor to create a potential difference of 1.5V across its plates? How much energy is stored in the capacitor in this case? b) How much charge would the battery have to supply to store 1.0J energy in the capacitor? What would be the potential across the capacitro in that case?

70. A parallel-plate capacitor is to be constructed by using a dielectric, rubber with dielectric constant of 3.20 and a dielectric strength of 20.0MV/m. The capacitro is to have a capacitance of 1.50 nF and must be able to withstand a maximum potential difference of 4.00kV. What is the minimum area the plates of the capacitor can have?

Jake responded:

The text at the bottom of 59. is hard to read. It says"
The potential difference, again, is the voltage supplied by the battery. This would not be the case if there were other elements in the circuit.

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Subject: Physics

Someone asked:

1. A charge of 28.0 nC is placed in a uniform electric field that is directed vertically upward and that has a magnitude of 4.00x 10^-4N/C. What work is done by the electric force when the charge moves (a) 0.450 m to the right. (b) 0.670 m upward. (c) 2.60 m at an angle of 45 degrees downward from the horizontal?

3. How far from a -7.20 mC point charge must a +2.30 mC point charge be plaed in order for the electric potential energy of the pair of charges to be -0.400J? (take the energy to be zero when the charges are infinitely far apart)

5. Two stationary point charges of +3.00nC and +2.00nC are separated by a distance of 50.0 cm. An electrons is released from rest at a point midway between the charges and moves along the line connecting them. What is the electric potential energy for the electron when it is (a) at the midpoint and (b) 10.0 cm from the +3.00nC charge?

8. A set of point charges is held in place at the vertices of an equilateral triangle of side 10.0 cm. Find the maximum amount of total kinetic energy that will be produced when the charges are released from rest in the frictionless void of outer space.

Jake responded:

Hey, So here is the PDF of it. Just let me know if you have any questions.

  • Scan001.PDF This attachment has been locked.

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Subject: Physics

Someone asked:

38. A proton traveling horizontally to the right at 4.50 x 10^6 m/s [use V^2=Vo=2a delta x]

a) find the magnitude and direction of the weakest electric field that can bring the proton uniformly to rest over a distance of 3.20 cm.
b)How much time does it take the proton to stop after entering the field?

40. Two point charges are separated by 25.0cm. Find the net electric field these charges produce at (a) point A
(b) point B. (c) What would be the magnitude and direction of the electric force this combination of charges would produce on a proton at A?

---B-------(-6.25nC)-----------A----------(-12.5nC)----
I__10.0cm_I I____10.0cm_I
I_______25.0cm________ I

52. Two point charges Q and +q (where q is positive) produce the net electric field shown at point P in the figure. The field points parallel to the line connecting the two charges. (a What can you conclude about the sign and magnitude of Q? Explain your reasoning. (b) if the lower charge were negative instead, would it be possible for the field to have the direction shown in the figure? Explain your reasoning. (Below is my attempt to show you the picture with the problem!)

Jake responded:

Hey Ali,

So I attached a pdf file with the written results and explanations. About half way through I switched to pencil so it is a bit lighter on the scan. If there is anything that is too light to read, just let me know.

I would really appreciate being your regular tutor for Physics 2, however I do have to warn you that there is a strong possibility that as the semester progresses I won't be able to help you anymore. This is due to how my physics 2 class ended. Long story short, my Physics 2 class did not fully cover what it was supposed to, we had to stop just short of optics.

But until that point I will be more than glad to help you.

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Subject: Physics

Someone asked:

Two protons close to each other are released from rest and are free to move. After being released (there may be more than one answer),
A. their speeds gradually decrease to zero as they move apart
B. their speeds gradually increase as they move apart
c. their accelerations gradually decrease to zero as they move apart
d. their acceleration gradually increase as they move apart

Jake responded:

Alright, Since protons have the same charge (+1) they will repel each other.

The equation of force between 2 charged object is F = Ke * (q1 * q2) / R^2
[where Ke is a constant, q1 and q2 are the charges, and R is the distance between them]

And the equation for acceleration is F = m*a

We can set these equal to each other and solve for acceleration.

m*a = Ke * (q1 * q2) / R^2

a = Ke * (q1 * q2) / R^2 *m

What is important to note here is that as R increases (ie. as the distance between the particles increases) acceleration will decrease.
a ~ 1/R^2

Therefore their acceleration will gradually decrease as they move apart.

We can now see that they will always have an increasing speed (due to acceleration) until the acceleration becomes zero at infinity. At this point they have obtained maximum speed.

So we can then see that their speeds will gradually increase as they move apart.

Feedback:

Subject: Trigonometry

InstaEDU asked:

What is Trigonometry?

Jake responded:

Trigonometry is the branch of Mathematics dealing with angles, lines, and associated lengths. Together these most often form right triangles, and those that do not can often be broken into right triangles. Using a few basic principles, one is able to acquire a plethora of information about the system. This is often a necessity in most mathematics and engineering topics.


Subject: Mechanical Engineering

InstaEDU asked:

What is Mechanical Engineering?

Jake responded:

Mechanical Engineering is a combination of the Principles involved in Physics, Mathematics, and Material Science. Together these three fields allow one to explore the effects of power, heat, forces, pressures, and temperatures on the material world around us. Using the knowledge gained from these explorations, one can design and create real world products to accomplish a multitude of tasks (i.e. transportation, energy generation, aeronautics, complimentary machines).

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